If it's not what You are looking for type in the equation solver your own equation and let us solve it.
x^2+2x-7.6=0
a = 1; b = 2; c = -7.6;
Δ = b2-4ac
Δ = 22-4·1·(-7.6)
Δ = 34.4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2)-\sqrt{34.4}}{2*1}=\frac{-2-\sqrt{34.4}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2)+\sqrt{34.4}}{2*1}=\frac{-2+\sqrt{34.4}}{2} $
| -5+m/14=-1 | | c−22=54 | | -9x+3x+8=12-5x | | 4p-p=21 | | 4x=9+1x | | 3x+4+x+2=30 | | 4-w=2.3 | | 7+6w+4w=-13 | | 10x-5115=180 | | -1-17y=-14-16y | | 2x+45+5x+56=150 | | 4-8x-24=2x | | x/6-2x=3 | | 10+0.1p=12+0.5p | | 4t-23=t+25 | | 5.55+16.2w=14.7w | | x+2/3=-7 | | -3=p/10 | | -8(5-4b)=-40-56 | | 2x+7=|x+1| | | 3x-27=1x+27 | | 6)=7(x–7) | | 20r-12r+(-16r)+(-7r)-(-14r)=(-15) | | -12x-3x+2=-223 | | 5.4x-9.8=6.4 | | -2(3x-3)-10=44 | | 1/2(b+2)3b=-1 | | -5+d=3d+2(d-7) | | 4-8x+24=2x | | |2m-8|-3=9 | | 19f+7=20f | | -6x+32=-6-4(1+5x) |